Issue 3 and Volume 69.

QUESTIONS AND ANSWERS Conducted by “He that questioneth much shall learn MUCH”-BACON NOTE—Readers of FIRE AND WATER ENGINEERING are invited to send in questions, which will be answered in the order in which they are received. Names are omitted from questions unless otherwise specified. Solving for Required Nozzle Pressure To the Editor: There is a question in “Practical Hydraulics for Firemen” in regard to a building 100 feet high, called A, page 183, which diagram appears on page 184, with the balance of the problem on pages 185 and 186. In the solution the formula used is 115 = 1/2 N. P. x 53, from which 1/2 N. P. equals 62, and N. P. = 124. Will you please work out said example and explain where the 124 pounds comes in. We will be very grateful to you for your trouble. Very truly yours, C. W. Fire Dept., Milwaukee, Wis.,…

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