Leadership

QUESTIONS and ANSWERS

Issue 9 and Volume 97.

QUESTIONS and ANSWERS Wherein are answered questions relating to current problems in Fire Protection. Finding Discharge To the Editor: 1,000-gallon pumper is pumping through 100 feet of 2 1/2-inch hose equipped with a 1 1/8-inch tip. Pump pressure is 120 pounds. How many gallons will this pump discharge? F. H. Answer: The solution to the problem is as follows: Nozzle pressure equals engine pressure divided by (1.1 + KL). K, which is a factor depending upon the nozzle and hose diameters is, for 2 1/2-inch hose and 1 1/8-inch nozzle, .167. L, the number of 50-foot lengths of hose in the line is found by dividing 100 by 50, giving 2. Then N. P. = 120 / (1.1 + .167 X 2) = 120 / (1.1 + .334) = 120 1.434 = 83.7, or 84 pounds approximately. The discharge from a 1 1/8-inch nozzle at 84 pounds pressure is 346…

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